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Gaussian Beams in Circular Hollow Metal Waveguides

One of the most important applications of the above equation is the propagation of Gaussian beams in hollow metal waveguides. In this case, the complex ABCD matrix is

$\displaystyle M_{system}=
 \left(
 \begin{array}{cc}
 A & B\\  
 C & D
 \end{ar...
...
 \right)
 =
 \left(
 \begin{array}{cc}
 1 & z\\  
 0 & 1
 \end{array}
 \right)$ (5)

and the input field has the form

$\displaystyle E_{x,in}(r_0^{\prime}) = E_0 exp(-r_0^{\prime 2}/w_0^{\prime 2})$ (6)

If we further define

$\displaystyle w_0^{\prime} \equiv w_0/D_0$ (7)

then the input field can be written

$\displaystyle E_0^\prime (r^\prime) \equiv i2 E_0 \frac{\hat{z}_0}{z} exp(-i\beta_0 z) 
 exp \left( -i \frac{\hat{z}_0}{z} r^{\prime 2} \right)$ (8)

The resulting output field components are

$\displaystyle E_1^\prime (r^\prime) \equiv \int_0^\infty
 exp \left[ -\left( \f...
...ft( 2 \frac{\hat{z}_0}{z} r_0^\prime r^\prime
 \right) 
 r_0^\prime dr_0^\prime$ (9)

and

$\displaystyle E_2^\prime (r^\prime) \equiv 
 exp \left( - \frac{1}{w_0^{\prime ...
...eft( 2 \frac{\hat{z}_0}{z} r_0^\prime r^\prime
 \right)
 r_0^\prime dr_0^\prime$ (10)

and it only remains to solve these two integrals.
next up previous
Next: References Up: Beam propagation in ABCD Previous: A New Diffraction Integral
Anthony Tovar 2003-10-31